为:ai=aZHjd或HZjdi
i
L5ixi=Li40R2L2s3缓和曲线上任意点i的坐标为:y=Lii6RLs
22缓和曲线ZH或HZ点到任意点i的弦长:Ci=xy
Xi=XZH或HZCicosai所以缓和曲线上任意点i的坐标为:Yi=YZH或HZCisi
ai
f例题:已知一段缓和曲线,ZH点到JD方向方位角为A183°17′089″,线路左偏43°31′02″,ZH点里程为K52001615,ZH点坐标x=388071927,y=508789089,R=960m,Ls=120m,求K52100处的中点坐标及左右各偏125m的坐标。解:根据已知条件可知:K52100到zh点的曲线长度Li=98385m
L2i180983852180i===22425642RLs2960120
K52100相对应的偏角:
L2i180983852180i====04885536RLs6960120
ZH点到K52100的方位角:
i
ai=aZHjdi=18317089048855=18229035
K52100左、右偏125m的方位角:
a左=Ai90=18052432690=180524326a左=Ai90=18052432690=270524326
K52100的直角坐标为:
L5i983855=98385=983676mxi=Li222240RL40960120s33y=Li=98385=13778mi6RLs6960120
缓和曲线ZH点到K52100的弦长:
Ci=x2y2=9836762137782=98377m
所以K52100的中线坐标为:
f92798377cos18229035=3879736424Xi=XZHCicosai=38807108998377si
18229035=5087848263Yi=YZHCisi
ai=508789
K52100左偏125m的坐标为:
6424125cos180524326=3879611439X左=Xi125cosa左=3879738263125si
180524326=5087846346Y左=Yi125si
a左=508784
K50200右偏125m的坐标为:
6424125cos270524326=3879738341X右=Xi125cosa右=3879738263125si
270524326=5087723278Y右=Yi125si
a右=508784
fr