1aAbBP
若cA0cB0ab则cAcBab

dcAdt
kcA
ba
cAkcA
2
2
2AP

dcAdt
kcA
2

cAcA0

dcAcA
2


t0
k2dt
1cA

1cA0
kt
t12
1kcA0

cA
dcAcA


cA0

t
kdt
0

级反应
11kt
1
1
1cAcA01
2
1
t12
1
1

1kcA0
f阿仑尼乌斯（Arrhe
ius）方程
dl
kdTEaRT
2

Ea
1RT
2

dl
kdT
l

k2k1

EaR

1T1

1T2

kAexp
EaRT

fr