6008001000120010001100ENDDATAMINSUMVARSQRTXA2YB2REND求得ab36010286514223最小值为：4423604。
八、婚配问题：
f10对年龄相当的青年，任意一对男女青年配对的概率pij见下表。试给出一个配对方案，使总的配对概率最大。w1w2w3w4w5w6w7w8w9w10m105828020910415402140068330451406085008410121002319m204235037980305006435021260043900158045440450802393m305155078330874403200083920027200164044180715900498m403340068080015009601062880312701901035330892800784m504329046110768007266013380012905869015360273106408m602259056780970804120020710384000576067560254801909m705798079420990107446060720683103676069920865608439m807604005920788902679062990092806315072750232401739m905298060290438704399037050035307176047840804901708m1006405005030498309334057510612406927055480908409943取xx_ij为01型决策变量。模型为：
modelsetsma
m1m10woma
w1w10li
kma
woma
pxe
dsetsdatap058280209104154021400683304514060850084101210023190423503798030500643502126004390015804544045080239305155078330874403200083920027200164044180715900498
f033400680800150096010628803127043290461107680072660133800129022590567809708041200207103840057980794209901074460607206831076040059207889026790629900928052980602904387043990370500353064050050304983093340575106124e
ddatamaxprodma
isumwoma
jpijxijforwoma
jsumli
kijxij1forma
isumli
kijxij1forli
kbi
xe
d
01901058690057603676063150717606927
03533015360675606992072750478405548
0892800784027310640802548019090865608439023240173908049017080908409943
求解结果：m1w5m2w8m3w2m4w4m5w7m6w3m7w6m8w1m9w9m10w10最大值为0055九、护士值班安排问题某医院，从周一到周日都要有人值班，每天至少需要的护士如表。要求每个护士每周连续上班5天，试问该医院至少需要多少护士？并给出上班安排计划。周1234567人20161316191412取决策变量star（i）周i开始值班的人数；目标函数mi
sumstari（i123，7约束条件：连续工作五天，周j值班的人数required（j）（j1237modelsetsdaysmo
su
requiredstarte
dsetsdata每天所需的最少职员数required20161316191412e
ddata最小化每周所需职员数mi
sumdaysstartfordaysJsumdaysIIle5startwrapJ2I7requiredJe
d解得：总共需要22人，周一8人开始值班，周二2人，r