001d
a100
1b10
01c1
11
21
1aba0c3dc21abaad1c11c1cd01d010
11321abadabcdabcdad111cd
5证明
a2abb212aab2bab3111
证明
a2abb2c2c1a2aba2b2a22aab2b2aba2b2a00111c3c11
4
f131
aba2b2a2babaabaab312ba2b2a
axbyaybzazbxxyz332aybzazbxaxbyabyzxazbxaxbyaybzzxy
证明
axbyaybzazbxaybzazbxaxbyazbxaxbyaybzxaybzazbxyaybzazbxayazbxaxbybzazbxaxbyzaxbyaybzxaxbyaybzxaybzzyzazbx2ayazbxxbzxaxbyzaxbyyxyaybz
2
xyzyzx3ayzxbzxyzxyxyz
3
xyzxyz3ayzxbyzxzxyzxy
3
xyzabyzxzxy
33
a2b232cd2
证明
a12b12c12d12
a22b22c22d22
a32b320c32d32
5
fa2b2c2d2
a12b12c12d12
a22b22c22d22
a32b32c4c3c3c2c2c1得c32d32
a22b2cd2a22b2cd2
1a42aa4
证明
2a12b12c12d12a12b12c12d1
1cc2c41dd2d4
2a32b32c32d32222
2a52b5cccc得2c543322d5
22022
1bb2b4
abacadbcbdcdabcd
1aa2a4
1bb2b4
1cc2c4
1dd2d4
11110bacada0bbaccadda0b2b2a2c2c2a2d2d2a2
bacada111bcdb2bac2cad2da
111bacada0cbdb0ccbcbaddbdba
6
fbacadacbdb
11ccbaddba
abacadbcbdcdabcd
x050a

10x100a
1a
2
0000x
a1x
1a
1xa
x1a2xa1
证明用数学归纳法证明当
2时D2
x1x2axa命题成立12a2xa1
假设对于
1阶行列式命题成立即D
1x
1a1x
2a
2xa
1则D
按第r