y
=,
方程变形得:y
=,
y2=5,可得y2=5或y2=,解得:y1=3,y2=.24.【解答】解:(1)①如图2中,结论:∠EPF=∠AEP∠CFP.
理由:∵AB∥CD.∴∠AEF∠CFE=180°,∴∠AEP∠CFP∠PEF∠PFE=180°,∵∠EPF∠PEF∠PFE=180°,∴∠EPF=∠AEP∠CFP.
②如图3中,结论:∠AEP∠EPF∠CFP=360°.
f理由:∵AB∥CD,∴∠AEF∠CFE=180°,∵∠PEF∠EPF∠PFE=180°,∴∠AEF∠PEF∠EPF∠CFE∠PFE=360°,∴∠AEP∠EPF∠CFP=360°.
(2)如图21中,结论:∠CFP=∠EPF∠AEP.如图22中,结论:∠AEP=∠EPF∠CFP.如图23中,结论:∠CFP=∠EPF∠AEP.如图24中,结论:∠AEP=∠EPF∠CFP.
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