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(最接近0的负数)即:22221负最小E11…1,M00…0,Ms110个21个即:22
91
15112
规格化所表示的范围用集合表示为:
222
9
1

22121
9
21
U2211511222221
9921
(4)最接近于0的正规格化数、负规格化数(由上题可得出)正规格化数E00…0,M100…0,Ms010个20个
222
9
1
负规格化数
E00…0,M011…1,Ms110个20个
2222
4.假设浮点数格式如下:Es(1)E1→E3MsM8M0
9121
2764
001101101101121
阶补码:尾数补码:机器数:111011011000111011011000
(2)
27001101101101102164
阶补码:尾数补码:机器数:111100101000111000101000
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5.(1)x011011y000011001101100000110011110xy011110无溢出2x011011y010101x补0011011y补11010110000110xy000110无溢出(3)x010110y000001x补1101010y补11111111101001xy010111无溢出6.(1)x011011y011111x补0011011y补00111110111010溢出(2)x010111y011011x补0010111y补11001011111100xy000100无溢出(3)x011011y010011x补y补溢出7.(1)原码阵列x011011y011111符号位x0y0011x原11011y原11111110111111111011110111101111011110111101000101001101100100110101110
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xy原1,1101000101直接补码阵列x补011011y补1000010110110000011010000000000000000000000000110110110111101100101110111111
xy补10010111011(直接补码阵列不要求)带求补器的补码阵列x补011011y补100001乘积符号位单独运算01=1尾数部分算前求补输出│X│=11011,│y│=111111110111110110111011010111111111
111110110X×Y=01101000101
00101
2原码阵列x011111y011011符号位x0y0110x补11111y补11011111111101111111111110000011111111111101000101xy补01101000101直接补码阵列x补100001y补100101
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10000110010110000100000010000100000000000010000110001100010111010r
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