轴相交，故斜率存在，设直线l方程为y＝kx－1，求得l与y轴交于M0，－k，又F坐标为10，设l交椭圆于Ax1，y1，Bx2，y2，
y＝kx－1，由x2y24＋3＝1，
消去y得3＋4k2x2－8k2x＋4k2－12＝0，4k2－128k2∴x1＋x2＝，x1x2＝，3＋4k23＋4k2→→又由MA＝λAF，∴x1，y1＋k＝λ1－x1，－y1，x1x2∴λ＝，同理μ＝，1－x11－x2x1＋x2－2x1x2x1x2∴λ＋μ＝＋＝1－x11－x21－x1＋x2＋x1x224k2－128k2－3＋4k23＋4k2
22
＝
8＝－34k－128k1－＋3＋4k23＋4k2
8所以当直线l的倾斜角变化时，直线λ＋μ的值为定值－3
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